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Question: Answered & Verified by Expert
18 glucose C6H12O6 is added to 178.2 g water. The vapour pressure of water (in torr) for this aqueous solution at 273 K is
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Options:
  • A 759.0
  • B 739.6
  • C 746.0
  • D 752.4
Solution:
1323 Upvotes Verified Answer
The correct answer is: 752.4
Relative lowering of vapour pressure

Equation P0-PsP0=Xsolute=nn+N

Modified forms of equation is P0-PsPs=nN

n = moles of solute, N = moles of solvent

P0=760 torr

Ps=?

760-PsPs=18180178.218

Ps=752.4 torr

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