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Question: Answered & Verified by Expert
${ }^{19} \mathrm{F}^{-1},~{ }^{16} \mathrm{O}^{-2},~{ }^{20} \mathrm{Ne}$ choose the correct statement
ChemistryStructure of AtomJIPMERJIPMER 2019
Options:
  • A Both $\mathrm{O}^{-2}$ and $\mathrm{F}^{-}$are isoelectronic
  • B All given have equal no of $e^{-}$
  • C $\mathrm{F}^{-}$and Ne have equal number of $\mathrm{e}^{-}$
  • D All of the above
Solution:
2763 Upvotes Verified Answer
The correct answer is: All of the above
The total number of electrons in the given species are as follows.
$\begin{aligned}
& { }_9^{19} \mathrm{~F}^{-1}=9+1=10 \\
& { }_8^{16} \mathrm{O}^{-2}=8+2=10 ;{ }_{10}^{20} \mathrm{Ne}=10
\end{aligned}$
Thus, all the given statements are correct.

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