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$\left(2^{3 n}-1\right)$ is divisible by
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Verified Answer
The correct answer is:
7
For $n=1,2^{3 n}-1$ has value $2^3-1=7$
For $n=2,2^{3 n}-1$ has value $2^n-1=63=7 \times 9$
which is divisible by 7 not by 6 or 8 or 9 .
Hence, option (2) is correct.
For $n=2,2^{3 n}-1$ has value $2^n-1=63=7 \times 9$
which is divisible by 7 not by 6 or 8 or 9 .
Hence, option (2) is correct.
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