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$2^{3 n}-7 n-1$ is divisible by
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Verified Answer
The correct answer is:
49
$2^{3 n}-7 n-1 \quad$ Taking $n=2 ;$
$$
\begin{array}{l}
2^{6}-7 \times 2-1 \\
=64-15=49
\end{array}
$$
Therefore this is divisible by 49 .
$$
\begin{array}{l}
2^{6}-7 \times 2-1 \\
=64-15=49
\end{array}
$$
Therefore this is divisible by 49 .
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