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$\int_2^5 2[x] d
18x=\{$ where $[x]$ denotes the greatest integer function $\leq x\}$
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18x=\{$ where $[x]$ denotes the greatest integer function $\leq x\}$
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The correct answer is:
18
$\begin{aligned} & \text { Let } I=\int_2^5 2[x] d x \\ & =\int_2^3 2(2) d x+\int_3^4 2(3) d x+\int_4^5 2(4) d x \\ & =4[x]_2^3+6[x]_3^4+8[x]_4^5=4+6+8=18\end{aligned}$
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