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$2 \cot ^2 \theta-\cot \theta-3=$
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The correct answer is:
$(2 \cot \theta-3)(\cot \theta+1)$
$\begin{aligned} & 2 \cot ^2 \theta-\cot \theta-3 \\ & =2 \cot ^2 \theta+2 \cot \theta-3 \cot \theta-3 \\ & =(2 \cot \theta-3)(\cot \theta+1)\end{aligned}$
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