Search any question & find its solution
Question:
Answered & Verified by Expert
2 g of a radioactive sample having half-life of 15 days was synthesised on 1st Jan 2009. The amount of the sample left behind on 1st March, 2009 (including both the days) is
Options:
Solution:
2597 Upvotes
Verified Answer
The correct answer is:
0.125 g
$N=N_0\left(\frac{1}{2}\right)^n$
Given, $\quad N_0=2 \mathrm{~g}$
$t_{1 / 2}=15$ days
$t=60$ days
$\Rightarrow \quad n=\frac{60}{15}=4$
$\therefore \quad N=2\left(\frac{1}{2}\right)^4$
or $\quad N=0.125 \mathrm{~g}$
Given, $\quad N_0=2 \mathrm{~g}$
$t_{1 / 2}=15$ days
$t=60$ days
$\Rightarrow \quad n=\frac{60}{15}=4$
$\therefore \quad N=2\left(\frac{1}{2}\right)^4$
or $\quad N=0.125 \mathrm{~g}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.