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Question: Answered & Verified by Expert
$2 \mathrm{MnO}_4^{-}+5 \mathrm{H}_2 \mathrm{O}_2+6 \mathrm{H}^{+} \rightarrow 2 \mathrm{Z}+5 \mathrm{O}_2+8 \mathrm{H}_2 \mathrm{O}$. In this reaction $\mathrm{Z}$ is
ChemistryRedox ReactionsJEE Main
Options:
  • A $\mathrm{Mn}^{+2}$
  • B $M n^{+4}$
  • C $\mathrm{MnO}_2$
  • D $M n$
Solution:
1020 Upvotes Verified Answer
The correct answer is: $\mathrm{Mn}^{+2}$
Hydrogen peroxide reduces \(\mathrm{Mn}(\mathrm{V}\)II) to \(\mathrm{Mn}\) (II) in acidic medium.
Thus \(\mathrm{Z}\) is \(\mathrm{Mn}^{2+}\).
Hence, option A is correct.

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