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$2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NO}_2(\mathrm{~g}), \frac{\mathrm{d}\left[\mathrm{NO}_2\right]}{\mathrm{dt}}=0.052 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}$. Calculate
$-\frac{\mathrm{d}\left[\mathrm{O}_2\right]}{\mathrm{dt}}$
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$-\frac{\mathrm{d}\left[\mathrm{O}_2\right]}{\mathrm{dt}}$
Solution:
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Verified Answer
The correct answer is:
$0.026 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}$
$\begin{aligned}-\frac{\mathrm{d}\left[\mathrm{O}_2\right]}{\mathrm{dt}} & =\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{NO}_2\right]}{\mathrm{dt}} \\ & =\frac{1}{2} \times 0.052 \\ & =0.026 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\end{aligned}$
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