Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert

2NOClg2NOg+Cl2g

In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol/L. The equilibrium constant at 30 °C is_____×10-4.

ChemistryChemical EquilibriumJEE MainJEE Main 2022 (27 Jun Shift 1)
Solution:
2311 Upvotes Verified Answer
The correct answer is: 125

2NOClg2NOg+Cl2g

t=02 M

t=teq2-xMxMx2M

 x=0.4 M

 NOCleq=1.6 M

NOeq=0.4 M

Cl2eq=0.2 M

Kc=NO2Cl2NOCl2=0.420.21.62

Kc=322.56×10-3

Kc=12.5×10-3

Kc=125×10-4

Integer answer is 125

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.