$ 2 \pi-\left(\sin ^{-1} \frac{4}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{16}{65}\right) $ is equal to :

Question

$ 2 \pi-\left(\sin ^{-1} \frac{4}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{16}{65}\right) $ is equal to :, $ \frac{\pi}{2} $, $ \frac{5 \pi}{4} $, $ \frac{3 \pi}{2} $, $ \frac{7 \pi}{4} $

MARKS App · Accepted Answer

sin - 1 4 5 + sin - 1 5 13 + sin - 1 16 65 = tan - 1 4 3 + tan - 1 5 12 + tan - 1 16 63 = tan - 1 4 3 + 5 12 1 - 4 3 · 5 12 + tan - 1 16 63 = tan - 1 63 16 + tan - 1 16 63 = π 2 ∴ 2 π - π 2 = 3 π 2

Search any question & find its solution

Looking for more such questions to practice?