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$2 \sin ^{-1} \frac{3}{5}+\cos ^{-1} \frac{24}{25}=$
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$\frac{\pi}{2}$
$\begin{aligned} & 2 \sin ^{-1} \frac{3}{5}+\cos ^{-1} \frac{24}{25}=\sin ^{-1} 2 \times \frac{3}{5} \sqrt{1-\frac{9}{25}}+\cos ^{-1} \frac{24}{25} \\ & \quad=\sin ^{-1} \frac{24}{25}+\cos ^{-1} \frac{24}{25}=\frac{\pi}{2}\end{aligned}$
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