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Question: Answered & Verified by Expert
2sin6θ+cos6θ-3sin4θ+cos4θ=
MathematicsTrigonometric Ratios & IdentitiesTS EAMCETTS EAMCET 2021 (05 Aug Shift 1)
Options:
  • A -1
  • B 1
  • C 0
  • D 12
Solution:
2612 Upvotes Verified Answer
The correct answer is: -1

2sin6θ+cos6θ-3sin4θ+cos4θ

=2sin2θ+cos2θ3-3sin2θcos2θsin2θ+cos2θ-3sin2θ+cos2θ2-2sin2θcos2θ

=21-3sin2θcos2θ-31-2sin2θcos2θ (Using sin2x+cos2x=1)

=-1-6sin2θcos2θ+6sin2θcos2θ

=-1

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