Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
2Zn+O22ZnO;ΔG°=-616 J

2Zn+S22ZnS;ΔG°=-293J

S2+2O22SO2;ΔG°=-408J

ΔG° for the following reaction

2ZnS+3O22ZnO+2SO2 is
ChemistryThermodynamics (C)JEE Main
Options:
  • A -731J
  • B -1317J
  • C -501J
  • D +731J
Solution:
2184 Upvotes Verified Answer
The correct answer is: -731J
For the reactions,

2ZnS2Zn+S2;ΔG°=+293J ...(i)

2Zn+O22ZnO;ΔG°=-616J ...(ii)

S2+2O22SO2;ΔG°=-408J ...(iii)

The ΔG° for the reaction,

2ZnS+3O22ZnO+2SO2

can be obtained by adding equations. (i), (ii) and (iii)

So, ΔG°=293-616-408=-731J

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.