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20 kV potential is applied across X-ray tube, the minimum wavelength of X-ray emitted will be
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$0.62 Å$
From relation, $\frac{h c}{\lambda_{\min }}=e V$ or $\quad \lambda_{\min }=\frac{h c}{e V}$
or $\begin{aligned} \lambda_{\min } & =\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{1.6 \times 10^{-19} \times 20 \times 10^3} \\ & =0.62 \times 10^{-10} \mathrm{~m}=0.62 Å\end{aligned}$
or $\begin{aligned} \lambda_{\min } & =\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{1.6 \times 10^{-19} \times 20 \times 10^3} \\ & =0.62 \times 10^{-10} \mathrm{~m}=0.62 Å\end{aligned}$
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