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$20 \mathrm{~mL}$ of methane is completely burnt using $50 \mathrm{~mL}$ of oxygen. The volume of the gas left after cooling to room temperature is
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The correct answer is:
$30 \mathrm{~mL}$
$\therefore$ Volume of gas left after cooling
$=10 \mathrm{mLO}_{2}+20 \mathrm{~mL} \mathrm{CO}_{2}=30 \mathrm{~mL}$
$\mathrm{H}_{2} \mathrm{O}(\mathrm{g})$ will be condense to $\mathrm{H}_{2} \mathrm{O}(\mathrm{l})$ after cooling.
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