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Question: Answered & Verified by Expert
2.0 molal aqueous solution of an electrolyte X2Y3 is 75% ionised. The boiling point of the solution a 1 atm is Kb(H2O)=0.52 K  kg  mol-1
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Options:
  • A 274.76 K
  • B 377 K
  • C 376.4 K
  • D 377.16 K
Solution:
1550 Upvotes Verified Answer
The correct answer is: 377.16 K
X2Y3(aq)2X3+(aq)+3Y2-aq

n=5

ΔTb=i  Kb.m=(1+4α) Kbm

=(1+4×0.75)×0.52×2

=4.16; Tb=373+4.16=374.76

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