20% of N 2 O 4 molecules are dissociated in a sample of gas at 27 ° C and 760 torr. Mixture has the density at equilibrium equal to

Question

20% of N 2 O 4 molecules are dissociated in a sample of gas at 27 ° C and 760 torr. Mixture has the density at equilibrium equal to, 1.48 g/L, 1.84 g/L, 2.25 g/L, 3.12 g/L

MARKS App · Accepted Answer

The reaction is N 2 O 4 ( g ) ⇌ 2 N O 2 ( g ) n = 2 and α = 20 100 = 0.2 D = 4.6, initial vapour density d = vapour density at equilibrium α = D - d ( n - 1 ) d 0.2 = 46 - d ( 2 - 1 ) d d = 38.3 Molar mass equilibrium = 2 × 38.3 = 76.6 PM = dRT Here, d = density of gas mixture d(mix) = PM RT = 1 × 76 .6 0 .0821 × 300 = 3 .12 g/L

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