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Question: Answered & Verified by Expert

25.0 mL of 0.050 M BaNO32 is mixed with 25.0 mL of 0.020 M NaF.Ksp of BaF2 is 0.5×106 at 298K. The ratio of Ba2+F-2 and Ksp is ______.

ChemistryIonic EquilibriumJEE MainJEE Main 2023 (13 Apr Shift 1)
Solution:
2510 Upvotes Verified Answer
The correct answer is: 5

Given:

Volume of Ba(NO3)2 solution = 25.0mL  Concentration of Ba(NO3)2 solution = 0.050M Volume of NaF solution = 25.0 mL  Concentration of NaF solution = 0.020M

Ba+2=25×0.0550=0.025M

F-=25×0.0250=0.01M

Ba+2 F-=25×10-7

Ksp=0.5×10-6=5×10-7

Ratio=Ba+2F-Ksp=25×10-75×10-7=5

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