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$250 \mathrm{~mL}$ of a sodium carbonate solution contains $2.65 \mathrm{~g}$ of $\mathrm{Na}_2 \mathrm{CO}_3$. If $10 \mathrm{~mL}$ of this solution is diluted to one litre, what is the concentration of the resultant solution?
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The correct answer is:
$10$
$\begin{aligned} & M=\frac{2.65}{106} \times \frac{1000}{250}=0.1 M \\ & M_1 V_1=M_2 V_2\end{aligned}$
$\begin{aligned} 0.1 \times 10 & =M_2 \times 1000 \\ M_2 & =\frac{0.1 \times 10}{1000}=0.001 \mathrm{M}\end{aligned}$
$\begin{aligned} 0.1 \times 10 & =M_2 \times 1000 \\ M_2 & =\frac{0.1 \times 10}{1000}=0.001 \mathrm{M}\end{aligned}$
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