28 g N 2 and 6 g H 2 were mixed. At equilibrium 17 g N H 3 was formed. The weight of N 2 and H 2 of equilibrium are respectively.

Question

28 g N 2 and 6 g H 2 were mixed. At equilibrium 17 g N H 3 was formed. The weight of N 2 and H 2 of equilibrium are respectively., 11 g, 20 g, 28 g, 6 g, 14 g, 3 g, None of these

MARKS App · Accepted Answer

Moles of N 2 = 28 28 = 1 , Moles of H 2 = 6 2 = 3 Moles of N H 3 = 17 17 = 1 Moles of N 2 = 1 2 = 14 g Moles of H 2 = 3 2 ⇒ 3 × 2 2 = 3 g .

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