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\( 3 \mathrm{~A} \rightarrow 2 \mathrm{~B} \), rate of reaction \( +\frac{d[B]}{d t} \) is equal to
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Verified Answer
The correct answer is:
\( -\frac{2}{3} d[A] \)
For reaction, $3 \mathrm{~A} \rightarrow 2 \mathrm{~B}$
Rate of appearance $=$ Rate of disappearance.
$+\frac{1}{2} \frac{d[B]}{d t}=-\frac{1}{3} \frac{d[A]}{d t}$
$\frac{d[B]}{d t}=-\frac{2}{3} \frac{d[A]}{d t}$
Rate of appearance $=$ Rate of disappearance.
$+\frac{1}{2} \frac{d[B]}{d t}=-\frac{1}{3} \frac{d[A]}{d t}$
$\frac{d[B]}{d t}=-\frac{2}{3} \frac{d[A]}{d t}$
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