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Question: Answered & Verified by Expert
\( 3 \mathrm{~A} \rightarrow 2 \mathrm{~B} \), rate of reaction \( +\frac{d[B]}{d t} \) is equal to
ChemistryChemical KineticsKCETKCET 2016
Options:
  • A \( -\frac{3 d[A]}{2 d t} \)
  • B \( -\frac{2}{3} d[A] \)
  • C \( +2 \frac{d[A]}{d t} \)
  • D \( -\frac{1}{3} \frac{d[A]}{d t} \)
Solution:
2722 Upvotes Verified Answer
The correct answer is: \( -\frac{2}{3} d[A] \)
For reaction, $3 \mathrm{~A} \rightarrow 2 \mathrm{~B}$
Rate of appearance $=$ Rate of disappearance.
$+\frac{1}{2} \frac{d[B]}{d t}=-\frac{1}{3} \frac{d[A]}{d t}$
$\frac{d[B]}{d t}=-\frac{2}{3} \frac{d[A]}{d t}$

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