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3 particles each of mass $m$ are kept at vertices of an equilateral triangle of side $L$. The gravitational field at centre due to these particles is
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Zero
Due to three particles net intensity at the centre
$I=I_A+I_B+I_C=0$
because out of these three intensities one equal in magnitude and the angle between each other is $120^{\circ}$.
$I=I_A+I_B+I_C=0$
because out of these three intensities one equal in magnitude and the angle between each other is $120^{\circ}$.
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