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30 mL of 0.1 M K I (aq) and 10 mL of 0.2 M AgN O 3 are mixed. The solution is then filtered out. Assuming no change in total volume, depression in freezing point of the resulting solution will be : (Given : Kf for H2O = 1.86 K kg mol-1, assume molarity = molality) 
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Solution:
2137 Upvotes Verified Answer
The correct answer is: 0.28
KI(aq) + AgNO 3 (aq) KNO 3( (aq) + AgI(s) millimoles 3 0 × 0 . 1 1 0 × 0 . 2 3 2 0 0 mm left 1 0 2 2

     [KI] in solution = 1 4 0  and [KNO3]   = 2 4 0 &
(Assuming molarity = molality for dilute soluation)
Δ T f =Δ T f (byKI)+Δ T f (byKN O 3 )
= molality × 1.86 × i KI + molality × 1.86 × i KNO 3
=( 1 40 ×1.86×2 )+( 2 40 ×1.86×2 )
= 0.093 + 0.186 = 0.279 = 0.28 °C

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