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$34.2 \mathrm{~g}$ sugar dissolved in $1 \cdot 8 \times 10^{2} \mathrm{~g}$ water to from sugar syrup, calculate mole fraction of sugar? (Molar mass sugar $=342$, water $=18$ )
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The correct answer is:
$0 \cdot 009$
Molar masses of cane sugar and water are $342 \mathrm{~g} / \mathrm{mol}$ and $18 \mathrm{~g} / \mathrm{mol}$ respectively.
Number of moles of can sugar $=\frac{34.2 \mathrm{~g}}{342 \mathrm{~g} / \mathrm{mol}}=0.1 \mathrm{~mol}$
Number of moles of water $=\frac{180 \mathrm{~g}}{18 \mathrm{~g} / \mathrm{mol}}=10 \mathrm{~mol}$
Mole fraction of cane sugar $=\frac{0.1}{0.1+10}=0.0099$
Number of moles of can sugar $=\frac{34.2 \mathrm{~g}}{342 \mathrm{~g} / \mathrm{mol}}=0.1 \mathrm{~mol}$
Number of moles of water $=\frac{180 \mathrm{~g}}{18 \mathrm{~g} / \mathrm{mol}}=10 \mathrm{~mol}$
Mole fraction of cane sugar $=\frac{0.1}{0.1+10}=0.0099$
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