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$\int_{\pi / 4}^{\pi / 2} \operatorname{cosec}^2 x d x =$
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The correct answer is:
1
$\int_{\pi / 4}^{\pi / 2} \operatorname{cosec}^2 x d x=[-\cot x]_{\pi / 4}^{\pi / 2}=-\left[\cot \frac{\pi}{2}-\cot \frac{\pi}{4}\right]=1$
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