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$\int_{-4}^{4} \log \left(\frac{8-x}{8+x}\right) d x=$
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0
$\begin{aligned} \text { Let } f(x) &=\log (8-x)-\log (8+x) \\ f(-x) &=\log (8+x)-\log (8-x) \\ &=-[\log (8-x)-\log (8+x)] \\ \text { Thus } f(-x) &=-f(x) \Rightarrow I=0 \end{aligned}$
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