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$\int_{-4}^4|x+2| d x=$
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The correct answer is:
20
$\begin{aligned} \int_{-4}^4|x+2| d x=\int_{-4}^2-(x+2) d x & +\int_{-2}^4(x+2) d x \\ & =\left|\frac{-x^2}{2}-2 x\right|_{-4}^{-2}+\left|\frac{x^2}{2}+2 x\right|_{-2}^4=20\end{aligned}$
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