Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert

4.5 moles each of hydrogen and iodine is heated in a sealed ten litre vessel.At equilibrium, 3 moles of HI were found. The equilibrium constant for H2g+I2g2HIg is ........

ChemistryChemical EquilibriumJEE MainJEE Main 2023 (11 Apr Shift 2)
Solution:
1272 Upvotes Verified Answer
The correct answer is: 1

The equilibrium moles of each reactant and product can be calculated as follows,

                                   H2g+I2g     2HIginitial                          4.5       4.5                 0At equilibrium       4.5-1.5  4.5-1.5       3

Now, using equilibrium moles, equilibrium constant calculated as shown below.
Keq=[HI]2H2I2=(3)23×3=1

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.