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4 batsman hits a ball of mass $0 \cdot 2 \mathrm{~kg}$ straight towards the bowler without changi initial speed of $6 \mathrm{~m} / \mathrm{s}$. What is the impulse imparted to the ball?
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The correct answer is:
2.4Ns
The impulse is equals to change in linear momentum.
Change in momentum $=\mathrm{m}(\mathrm{v}-\mathrm{u})$ $=0.2(-6-6)=-2.4$
The negative sign shows the direction of impulse is from batsman to bowler.
Change in momentum $=\mathrm{m}(\mathrm{v}-\mathrm{u})$ $=0.2(-6-6)=-2.4$
The negative sign shows the direction of impulse is from batsman to bowler.
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