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4 boys and 2 girls occupy seats in a row at random. Then the probability that the two girls occupy seats side by side is
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Verified Answer
The correct answer is:
\(\frac{1}{3}\)
\(\begin{gathered} \text {Hints: }
\mathrm{n}(\mathrm{e})=\lfloor 5 \cdot\lfloor 2 \\
\mathrm{n}(\mathrm{s})=\lfloor 6 \\
\mathrm{p}=\frac{\lfloor 5 \cdot \lfloor 2}{\lfloor 6}=\frac{2}{6}=\frac{1}{3}
\end{gathered}\)
\mathrm{n}(\mathrm{e})=\lfloor 5 \cdot\lfloor 2 \\
\mathrm{n}(\mathrm{s})=\lfloor 6 \\
\mathrm{p}=\frac{\lfloor 5 \cdot \lfloor 2}{\lfloor 6}=\frac{2}{6}=\frac{1}{3}
\end{gathered}\)
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