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$4 \mathrm{~L}$ -atm is equal to
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$96 \mathrm{cal}$
$\begin{aligned} \because 1 \mathrm{~L}-\mathrm{atm} &=101.266 \mathrm{~J} \\ \therefore 4 \mathrm{~L}-\mathrm{atm} &=101.266 \times 4 \mathrm{~J} \\ &=405.06 \mathrm{~J} \\ &=\frac{405.06}{4.2} \mathrm{cal} \quad[\because 1 \mathrm{cal}=4.2 \mathrm{~J}] \\ &=96.4 \mathrm{cal} \end{aligned}$
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