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Question: Answered & Verified by Expert
4 mol of a mixture of Mohr's salt and Fe2SO43 requires 500 ml of 1 M, K2Cr2O7 for complete oxidation in acidic medium. The mole % of the Mohr's salt in the mixture is
ChemistrySome Basic Concepts of ChemistryJEE Main
Options:
  • A 25
  • B 50
  • C 60
  • D 75
Solution:
1093 Upvotes Verified Answer
The correct answer is: 75
Cr2O72-+6Fe2+(n=1) (Mohr's salt) +14H+2Cr3++6Fe3++7H2O

Equivalent of Fe2+= moles of Mohr's salt

= equivalent of K2Cr2O7

=500×10-3×6×1=3

Hence mole percent of Mohr's salt

=34×100=75

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