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4 moles each of $\mathrm{SO}_{2}$ and $\mathrm{O}_{2}$ gases are allowed to react to form $\mathrm{SO}_{3}$ in a closed vessel. At equilibrium $25 \%$ of $\mathrm{O}_{2}$ is used up. The total number of moles of all the gases present at equilibrium is
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Verified Answer
The correct answer is:
$7.0$
$$
\begin{aligned}
&\begin{array}{lccc}
& 2 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons & 2 \mathrm{SO}_{3} \\
\text { Initially } & 4 \text { moles } & 4 \text { moles } & 0 \\
\text { At equili. } & (4-2) & (4-0.25 \times 4) & 2 \\
& =2 & =3 &
\end{array}\\
&\therefore \text { Total moles at equilibrium }=2+3+2=7 \text { moles. }
\end{aligned}
$$
\begin{aligned}
&\begin{array}{lccc}
& 2 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons & 2 \mathrm{SO}_{3} \\
\text { Initially } & 4 \text { moles } & 4 \text { moles } & 0 \\
\text { At equili. } & (4-2) & (4-0.25 \times 4) & 2 \\
& =2 & =3 &
\end{array}\\
&\therefore \text { Total moles at equilibrium }=2+3+2=7 \text { moles. }
\end{aligned}
$$
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