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4 moles of $A$ are mixed with 4 moles of $B$. At equilibrium for the reaction $A+B \rightleftharpoons C+D, 2$ moles of $C$ and $D$ are formed. The equilibrium constant for the reaction will be
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$A+B \Rightarrow C+D$
Initial conc. 4,4 0 0
After $T$ time conc. (4-2) (4-2) 2 2
Equilibrium constant $=\frac{[C][D]}{[A][B]}=\frac{2 \times 2}{2 \times 2}=1$
Initial conc. 4,4 0 0
After $T$ time conc. (4-2) (4-2) 2 2
Equilibrium constant $=\frac{[C][D]}{[A][B]}=\frac{2 \times 2}{2 \times 2}=1$
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