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$450 \mathrm{mg}$ of glucose is dissolved in $100 \mathrm{~g}$ of solvent. What is the molality of solution?
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Verified Answer
The correct answer is:
$0.025 \mathrm{~m}$
Molality $=\frac{\text { moles of solute } \times 1000}{\text { weight of solvent (in g) }}$
Or $=\frac{\text { weight of solute } \times 1000}{\text { mol. wt of solute } \times \text { weight of solvent (in g) }}$
$$
=\frac{450 \times 10^{-3} \times 1000}{180 \times 100}
$$
$[\because$ Mol. mass of glucose $=180]$
$=0.025 \mathrm{~m}$
Or $=\frac{\text { weight of solute } \times 1000}{\text { mol. wt of solute } \times \text { weight of solvent (in g) }}$
$$
=\frac{450 \times 10^{-3} \times 1000}{180 \times 100}
$$
$[\because$ Mol. mass of glucose $=180]$
$=0.025 \mathrm{~m}$
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