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Question: Answered & Verified by Expert
46. If $M(A ; Z), M_p$ and $M_n$ denote the masses of the nucleus ${ }_Z^A X$, proton and neutron respectively in units of $\mathrm{u}\left(1 \mathrm{u}=931.5 \mathrm{MeV} / \mathrm{C}^2\right)$ and $\mathrm{BE}$ represents its bonding energy in $\mathrm{MeV}$, then
PhysicsNuclear PhysicsNEETNEET 2008 (Mains)
Options:
  • A $M(A, Z)=Z M_p+(A-Z) M_n+\mathrm{BE} / C^2$
  • B $M(A, Z)=Z M_p+(A-Z) M_n-\mathrm{BE} / \mathrm{C}^2$
  • C $$
    \begin{aligned}
    & M(A, Z)=Z M_p+(A-Z) M_n+B E \\
    \end{aligned}
    $$
  • D $$
    \begin{aligned}
    & M(A, Z)=Z M_p+(A-Z) M_n-B E
    \end{aligned}
    $$
Solution:
1202 Upvotes Verified Answer
The correct answer is: $M(A, Z)=Z M_p+(A-Z) M_n-\mathrm{BE} / \mathrm{C}^2$
$$
\mathrm{BE}=\left[\mathrm{ZM}_{\mathrm{p}}+(\mathrm{A}-\mathrm{Z}) \mathrm{M}_{\mathrm{n}}-\mathrm{M}(\mathrm{A}, \mathrm{Z})\right] \mathrm{C}^2
$$

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