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$5 \mathrm{~L}$ of $\mathrm{NaOH}$ solution of $\mathrm{pH} 12$ contains
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$2 \mathrm{~g}$
$M_{1}=5 \mathrm{~L}$ and pH $=12$ $$ \mathrm{pOH}=14-\mathrm{pH}=14-12=2 $$ ${[\mathrm{OH}]=10^{-\text {pOH }}=10^{-2} }$
$\therefore$ Mass of $\mathrm{NaOH}=$ moles $\times$ molar mass
$\therefore$ Mass of $\mathrm{NaOH}=$ moles $\times$ molar mass
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