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$5 \mathrm{~mL}$ of $0.4 \mathrm{~N} \mathrm{NaOH}$ is mixed with $20 \mathrm{~mL}$ of $0.1 \mathrm{~N} \mathrm{HCl}$. The $\mathrm{pH}$ of the resulting solution will be
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From the first law of thermodynamics, the total energy of the universe remains constant.
$$
\begin{aligned}
&\text { Milliequivalents of } \mathrm{NaOH}=\mathrm{N}_{1} \mathrm{~V}_{1} \\
&\qquad=0.4 \times 5=0.20 \\
&\text { Milliequivalents of } \mathrm{HCl}=\mathrm{N}_{2} \mathrm{~V}_{2} \\
&\qquad=0.1 \times 20=0.20
\end{aligned}
$$
$$
\begin{aligned}
&\text { Milliequivalents of } \mathrm{NaOH}=\mathrm{N}_{1} \mathrm{~V}_{1} \\
&\qquad=0.4 \times 5=0.20 \\
&\text { Milliequivalents of } \mathrm{HCl}=\mathrm{N}_{2} \mathrm{~V}_{2} \\
&\qquad=0.1 \times 20=0.20
\end{aligned}
$$
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