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$50 \Omega$ and $100 \Omega$ resistors are connected in series. This connection is connected with a battery of $2.4 \mathrm{~V}$. When a voltmeter of $100 \Omega$ resistance is connected across $100 \Omega$ resistor, then the reading of the voltmeter will be
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Verified Answer
The correct answer is:
$1.2 \mathrm{~V}$
Equivalent resistance of the circuit
$$
R_{e q}=100 \Omega
$$
Current through the circuit, $i=\frac{V}{R}=\frac{2.4}{100} \mathrm{~A}$
Potential difference across combination of voltmeter and $100 \Omega$ resistance
$$
=\frac{2.4}{100} \times 50=1.2 \mathrm{~V}
$$
Since the voltmeter and $100 \Omega$ resistance are in parallel, the voltmeter reads the same value i.e., $1.2 \mathrm{~V}$.
$$
R_{e q}=100 \Omega
$$
Current through the circuit, $i=\frac{V}{R}=\frac{2.4}{100} \mathrm{~A}$
Potential difference across combination of voltmeter and $100 \Omega$ resistance
$$
=\frac{2.4}{100} \times 50=1.2 \mathrm{~V}
$$
Since the voltmeter and $100 \Omega$ resistance are in parallel, the voltmeter reads the same value i.e., $1.2 \mathrm{~V}$.
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