50 g of ice at 0 ° C is mixed with 50 g of water at 80 ° C . The final temperature of the mixture is (latent heat of fusion of ice = 80 c a l / g , s w = 1 c a l / g ° C )

Question

50 g of ice at 0 ° C is mixed with 50 g of water at 80 ° C . The final temperature of the mixture is (latent heat of fusion of ice = 80 c a l / g , s w = 1 c a l / g ° C ), 0 ° C, 40 ° C, 60 ° C, less than 0 ° C

MARKS App · Accepted Answer

The heat required by the ice Q = m × L = 50 × 80 = 4000 c a l the heat released by water Q = m s Δ θ = 50 × 1 × 80 = 4000 c a l both are equal. Final temperature = 0 ° C

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