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Question: Answered & Verified by Expert
50 mL solution of pH = 1 is mixed with 50 mL solution of pH = 2. The pH of mixture will be nearly
ChemistrySome Basic Concepts of ChemistryNEET
Options:
  • A 0.76
  • B 1.26
  • C 1.76
  • D 2.26
Solution:
2676 Upvotes Verified Answer
The correct answer is: 1.26
-log[H3O+]=1
So [H3O+]=10-1M=0.1M
and -log[H3O+]=2
So [H3O+]=10-2M=0.01M
Number of mili mole in 50 mL of 0.1 M H3O+=5 mili mole H3O+
Number of mili mole in 50 mL of 0.01 M H3O+=0.5milmoleH3O+
Total milimole H3O+ in 100 mL solution = 5 + 0.5 = 5.5 mili mole
Hence, [H3O+]=5.5 milmole100 mL=0.055 M
So pH =-log[H3O+]=-log(0.055)=1.26 .

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