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$50 \%$ of first order reaction is completed in $30 \mathrm{~min}$. The velocity constant of the reaction is
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Verified Answer
The correct answer is:
$0.0231$
As reaction is completed $50 \% \mathrm{so}, t_{1 / 2}=30 \mathrm{~min}$.
For first order reaction
$$
k=\frac{0.693}{t_{1 / 2}}=\frac{0.693}{30}=0.023 \mathrm{imin}^{-1}
$$
For first order reaction
$$
k=\frac{0.693}{t_{1 / 2}}=\frac{0.693}{30}=0.023 \mathrm{imin}^{-1}
$$
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