6 × 10 − 3 mole K 2 Cr 2 O 7 reacts completely with 9 × 10 − 3 mole of X n+ to give XO 3 - and Cr 3 + . Value of n will be

Question

6 × 10 − 3 mole K 2 Cr 2 O 7 reacts completely with 9 × 10 − 3 mole of X n+ to give XO 3 - and Cr 3 + . Value of n will be, 1, 3, 2, 4

MARKS App · Accepted Answer

X n + → X + 5 O 3 - + 5 - n e - Cr 2 O 7 2 - + 1 4 H + + 6 e - → 2 Cr 3 + + 7 H 2 O Making no. of moles of electrons same for oxidation and reduction reaction 6 × 1 0 - 3 × 6 = 5 - n × 9 × 1 0 - 3 Implies n = 1

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