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Question: Answered & Verified by Expert
6 mol of a mixture of Mohr's salt and Fe2(SO4)3 requires 500 ml of 1 M of K2Cr2O7 for complete oxidation in acidic medium. The mole % of the Mohr's salt in the mixture is
ChemistryRedox ReactionsNEET
Options:
  • A 75
  • B 50
  • C 60
  • D 25
Solution:
1513 Upvotes Verified Answer
The correct answer is: 50
Cr2O72-+6Fe2+(n=1) (Mohr's salt) +14H+2Cr3++6Fe3++7H2O
Equivalent of Fe2+= moles of Mohr's salt
= equivalent of K2Cr2O7
=500×10-3×6×1=3
Hence mole percent of Mohr's salt
=36×100=50

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