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Question: Answered & Verified by Expert
\( 60 \mathrm{~g} \) of gaseous \( \mathrm{C}_{2} \mathrm{H}_{6} \) is mixed with \( 28 \mathrm{~g} \) of carbon monoxide. The pressure of the resulting gaseous mixture is \( 3 \) atm. The partial pressure in atm of \( \mathrm{C}_{2} \mathrm{H}_{6} \) in the mixture is
ChemistryStates of MatterJEE Main
Solution:
1653 Upvotes Verified Answer
The correct answer is: 2
Moles of C2H6=60g30g/mol=2mol
moles of CO=28g28g/mol=1mol
Mole fraction C2H6=22+1=23
Partial pressure of C2H6=Ptotal× Mole fraction of C2H6
=3atm×23=2atm .
 

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