6.02 × 1 0 20 molecules urea are present in 100 mL of its solution. The molarity of solution is

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6.02 \times 1 0^{20}

molecules urea are present in 100 mL of its solution. The molarity of solution is

ChemistrySome Basic Concepts of ChemistryNEET

Options:

A 0.01 M
B 0.001 M
C 0.1 M
D 0.02 M

Solution:

1851 Upvotes Verified Answer

The correct answer is: 0.01 M

n = \frac{6.02 \times 1 0^{20}}{6.02 \times 1 0^{23}} = 0.001

M = \frac{n}{V} \times 1000 = \frac{0.001}{100} \times 1000 = 0.01

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