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$7^{2 \log _{7} 5}$ is equal to
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Verified Answer
The correct answer is:
25
We have,
$7^{2 \log 5} 5$
$=7^{\log _{7} 5^{2}}$
$=5^{2}$
[ $m \log a=\log a^{m}$ ]
$\left[a^{\log _{a} b}=b\right]$
$=25$
$7^{2 \log 5} 5$
$=7^{\log _{7} 5^{2}}$
$=5^{2}$
[ $m \log a=\log a^{m}$ ]
$\left[a^{\log _{a} b}=b\right]$
$=25$
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