Search any question & find its solution
Question:
Answered & Verified by Expert
$7^{\text {th }}$ term of the sequence $\sqrt{2}, \sqrt{10}, 5 \sqrt{2}, \ldots \ldots$ is
Options:
Solution:
1431 Upvotes
Verified Answer
The correct answer is:
$125 \sqrt{2}$
Given sequence is $\sqrt{2}, \sqrt{10}, \sqrt{50} \ldots \ldots$ Common ratio $r=\sqrt{5}$, first term $a=\sqrt{2}$, then $7^{\text {th }}$ term
$t_7=\sqrt{2}(\sqrt{5})^{7-1}=\sqrt{2}(\sqrt{5})^6=\sqrt{2}(5)^3=125 \sqrt{2}$
$t_7=\sqrt{2}(\sqrt{5})^{7-1}=\sqrt{2}(\sqrt{5})^6=\sqrt{2}(5)^3=125 \sqrt{2}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.