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$80 \mathrm{~g}$ of oxygen contains as many atoms as in
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$5 \mathrm{~g}$ of hydrogen
Number of moles of oxygen $=\frac{80}{16}$
Number of atoms of oxygen $=\frac{80}{16} \times \mathrm{N}_{0} \times 2$
$$
=5 \times \mathrm{N}_{0} \times 2
$$
Number of moles of $5 \mathrm{~g}$ of hydrogen $=\frac{5}{1}$
Number of atoms in $5 \mathrm{~g}$ of hydrogen $=5 \times \mathrm{N}_{0} \times 2$
Hence, the number of atoms in $80 \mathrm{~g}$ of oxygen is equal to the number of atoms in $5 \mathrm{~g}$ of hydrogen.
Number of atoms of oxygen $=\frac{80}{16} \times \mathrm{N}_{0} \times 2$
$$
=5 \times \mathrm{N}_{0} \times 2
$$
Number of moles of $5 \mathrm{~g}$ of hydrogen $=\frac{5}{1}$
Number of atoms in $5 \mathrm{~g}$ of hydrogen $=5 \times \mathrm{N}_{0} \times 2$
Hence, the number of atoms in $80 \mathrm{~g}$ of oxygen is equal to the number of atoms in $5 \mathrm{~g}$ of hydrogen.
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